A seq with a strange behavior (or not)?
Hello Math-Fun,
NAME
Lexicographically earliest sequence of positive integers such that the nth pair of identical terms encloses exactly a(n) terms.
DATA
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, …
COMMENTS
To extend S we try first to find the smallest existing term that doesn’t lead to a contradiction. If all existing terms lead to a contradiction, we try the smallest term not present in S that doesn’t lead to a contradiction.
EXAMPLE
For n = 1, we have a(1) = 1 and the 1st constructed pair encloses 1 term: [1, 2, 1]
For n = 2, we have a(2) = 2 and the 2nd constructed pair encloses 2 terms: [2, 1, 3, 2]
For n = 3, we have a(3) = 1 and the 3rd constructed pair encloses 1 term: [3, 2, 3]
For n = 4, we have a(4) = 3 and the 4th constructed pair encloses 3 terms: [1, 3, 2, 3, 1]
For n = 5, we have a(5) = 2 and the 5th constructed pair encloses 2 terms: [2, 3, 1, 2]
For n = 6, we have a(6) = 3 and the 6th constructed pair encloses 3 terms: [3, 1, 2, 4, 3]
For n = 7, we have a(7) = 1 and the 7th constructed pair encloses 1 term: [4, 3, 4]
etc.
Why is the word *constructed* present in the above Example section?
Imagine a person A checking if S works as intended.
A will read S term by term and ask itself at every stage: to what *enclosing pair* does this a(n) belong?
Well, a(1) = 1 will be interpreted as the *opening bracket* of the first pair [1,1]; A will then check how many integers are enclosed by [1, 1] (answer: one integer, which is correct, the integer 2).
A would then read (from left to right) a(2) = 2 as the *opening bracket* of the second pair [2,2], then check how many integers are enclosed by [2, 2] (answer: two integers, which is correct, the integers 1 and 3).
Now comes a(3) = 1, which A might (incorrectly) see as the *opening bracket* of the third pair [1,1] — instead of the *closing bracket* of the first pair! If A, looking to the right, checks how many integers are enclosed by the next [1, 1], A will think that something is wrong: _three_ integers are enclosed there (the integers 3, 2, 3), which doesn’t match the value _1_ of a(3).
The word *constructed* is intended to avoid the above misinterpretation.
Indeed, when building the start of S, the third pair to appear was [3, 3], correctly enclosing _one_ single integer, which is a(5) = 2.
_Then_ was built the fourth pair [1, 1], correctly enclosing the _three_ integers 3, 2 and 3… See the hereunder way of building S.
__________________________________
Successive enclosing pairs (in yellow) and enclosed
terms (in blue + underlined); the successive sizes of the blue underlined chunks
reproduce the sequence S itself:
[Chunk size]
S = 1,
2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6,
9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [1]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3,
7, 4, 6, 8, 9, … [2]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3,
6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [1]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6,
7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [3]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6,
8, 9, … [2]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [3]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3,
4, 5, 3, 6, 7, 4,
3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [1]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4,
5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6,
8, 9, … [2]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4,
10, 3, 7, 4, 6, 8, 9, … [4]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [3]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7,
4, 6, 8, 9, … [4]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [5]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [3]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9,
… [6]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [7]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [4]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [3]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [8]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [6]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, … [9]
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3,
8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, …
More terms coming soon (computed by hand)
Best,
É.
_____________
Update with more terms — and two questions:
S = 1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, 11, 10, 12, 3, 9, 13, 7, 3, 11, 9, 14, 15, 13, 16, 17, 7, 18, 3, 19, 20, 11, 14, 9, 20, 17, 15, 19, 20, 18, 21, 11, 22, 3, 23, 24, 25, 26, 14, 17, 9, 27, 28, 29, 15, 26, 19, 29, ...
a) It seems that 1 and 2 will never show again... But who knows? And we have only one 5... but ten 3s so far... Is there a logic in the integers occurrences/densities?
b) S grows very slowly... but will S grow like this forever? Is it possible for S to enter a loop? Or to produce a growing pattern like Langton’s ant "highway"?
Best,
É.
_____________
Update (next day)
Gavin L. was quick to extend S:
> I saw your "A seq with a strange behavior (or not)?" and was very intrigued, so I wrote some code.
Here are some more terms!
1, 2, 1, 3, 2, 3, 1, 2, 4, 3, 4, 5, 3, 6, 7, 4, 3, 8, 6, 9, 7, 8, 4, 10, 3, 7, 4, 6, 8, 9, 11, 10, 12, 3, 9, 13, 7, 3, 11, 9, 14, 15, 13, 16, 17, 7, 18, 3, 19, 20, 11, 14, 9, 20, 17, 15, 19, 20, 18, 21, 11, 22, 3, 23, 24, 25, 26, 14, 17, 9, 27, 28, 29, 15, 26, 19, 29, 20, 30, 18, 17, 31, 14, 15, 23, 32, 33, 9, 34, 35, 26, 28, 36, 37, 38, 39, 19, 30, 29, 9, 20, 30, 40, 18, 41, 17, 42, 31, 43, 14, 39, 37, 40, 32, 44, 33, 45, 46, 34, 18, 47, 38, 48, 49, 41, 50, 19, 42, 51, 29, 37, 32, 20, 34, 52, 18, 40, 53, 17, 54, 55, 31, 20, 43, 56, 14, 57, 47, 58, 59...
(In progress)
Bravo Gavin and merci!
(for the extension, the submission and the hereunder graph!-)
Double reflection
Commentaires
Enregistrer un commentaire