Chunk & Sum
[a lot of stuff erased from the last 3 days]
____________________
Update October 29th, 2019:
Hello Math-Funsters and Seqfans,
forget the mails I've sent recently to both your mailing lists, they were criticized by so many people(for Vantablack obscurity) that I've decided to rephrase the Chunk & Sum idea from scratch...
Imagine I give you the 10 wooden blocks shown here – each one is marked with an integer taken from the set 1 to 10.
It is asked to concatenate those blocks to form a single integer – for instance the 11-digit integer 51263478910.
The next step is to chunk this number in as many pieces as you want – but you must obey three rules:
Rule (0): you cannot cut between the digits of a single block marked with an integer > 9 (this means here that you don't split the 1 and the 0 of "10").
Rule (1): the chunks must be monotonically increasing.
Rule (2): their sum must be the smallest possible one.
Example:
According to the rule (1) we can chunk 51263478910 (the above integer) in a lot of different ways; here are a few legal ones:
a) 51263478910 --> 5 /1263478910
b) 51263478910 --> 5 /12 /634 /78910
c) 51263478910 --> 51 /263 / 478 / 910
d) 51263478910 --> 512 / 6347 / 8910
e) 51263478910 --> 51263478910 (a single chunk is always possible)
f) 51263478910 --> 5 / 12634 / 78910
g) 51263478910 --> 51263 / 478910
h) ...
Now if we make, line by line, the sum of the chunks, we'll get:
a) 5 + 1263478910 = 1263478915
b) 5 + 12 + 634 + 78910 = 79561
c) 51 + 263 + 478 + 910 = 1702
d) 512 + 6347 + 8910 = 15769
e) 51263478910
f) 5 + 12634 + 78910 = 91549
g) 51263 + 478910 = 530173
h) ...
We will declare that the smallest sum wins the "Chunk & Sum" game.
The answer (c), above, beats the others, yes, but the real winner is 5+12+63+478+910 with sum 1468. Impossible to chunk the starting 51263478910 in monotonically increasing chunks having an inferior sum.
Lets call this 1468 the golden sum of 51263478910.
[Side note]:
The "Chunk & Sum" game was inspired by this sequence, which I had completely forgotten, signed by Dan Hoey and me eleven years ago. Its definition could be adapted to this game:
And now for the real challenge!
The real challenge is to give Alice and Bob a bunch of blocks, marked 1 to n, and ask them to cooperate to form an integer who's golden sum beats any other one, obtained with the same blocks!
For our 1 to 10 example above, we've used the concatenation 51263478910 with golden sum 1468. But the best reordering of the 1 to 10 blocks is 98471106532 with golden sum 107101 (found by Frank Stevenson).
Here is the beginning of a sequence of such golden sums that might enter the OEIS – all its terms were computed by Frank Stevenson – and I thank him 1000 times!
Best,
É.
L'idée que développe cette page, m'est venue hier soir alors que je cherchais dans l'OEIS des occurrences du mot "Skolem" (je dois envoyer un petit texte sur le sujet à la revue Tangente). Je suis tombé sur cette suite [https://oeis.org/A143789] qui date de 2008, et j'ai trouvé que sa définition et les premières lignes de la section "Comments" avaient été particulièrement bien écrites (par Dan Hoey). Je me suis demandé ce qu'était devenu Dan, j'ai cliqué sur son nom et lu ceci :
____________________
Update October 29th, 2019:
Hello Math-Funsters and Seqfans,
forget the mails I've sent recently to both your mailing lists, they were criticized by so many people(for Vantablack obscurity) that I've decided to rephrase the Chunk & Sum idea from scratch...
Imagine I give you the 10 wooden blocks shown here – each one is marked with an integer taken from the set 1 to 10.
It is asked to concatenate those blocks to form a single integer – for instance the 11-digit integer 51263478910.
The next step is to chunk this number in as many pieces as you want – but you must obey three rules:
Rule (0): you cannot cut between the digits of a single block marked with an integer > 9 (this means here that you don't split the 1 and the 0 of "10").
Rule (1): the chunks must be monotonically increasing.
Rule (2): their sum must be the smallest possible one.
Example:
According to the rule (1) we can chunk 51263478910 (the above integer) in a lot of different ways; here are a few legal ones:
a) 51263478910 --> 5 /1263478910
b) 51263478910 --> 5 /12 /634 /78910
c) 51263478910 --> 51 /263 / 478 / 910
d) 51263478910 --> 512 / 6347 / 8910
e) 51263478910 --> 51263478910 (a single chunk is always possible)
f) 51263478910 --> 5 / 12634 / 78910
g) 51263478910 --> 51263 / 478910
h) ...
Now if we make, line by line, the sum of the chunks, we'll get:
a) 5 + 1263478910 = 1263478915
b) 5 + 12 + 634 + 78910 = 79561
c) 51 + 263 + 478 + 910 = 1702
d) 512 + 6347 + 8910 = 15769
e) 51263478910
f) 5 + 12634 + 78910 = 91549
g) 51263 + 478910 = 530173
h) ...
We will declare that the smallest sum wins the "Chunk & Sum" game.
The answer (c), above, beats the others, yes, but the real winner is 5+12+63+478+910 with sum 1468. Impossible to chunk the starting 51263478910 in monotonically increasing chunks having an inferior sum.
Lets call this 1468 the golden sum of 51263478910.
[Side note]:
The "Chunk & Sum" game was inspired by this sequence, which I had completely forgotten, signed by Dan Hoey and me eleven years ago. Its definition could be adapted to this game:
« Lightest finite monotonically increasing sequence obtained by chunking a given integer. »
"Lightest" --> the weight of such a sequence is the sum of all its terms;
"Finite" --> by definition all such sequences are finite;
"Monotonically" --> no two adjacent terms in the sequence are the same;
"Increasing" --> a(n) < a(n+1);
"Chunking" --> cutting in slices.
And now for the real challenge!
The real challenge is to give Alice and Bob a bunch of blocks, marked 1 to n, and ask them to cooperate to form an integer who's golden sum beats any other one, obtained with the same blocks!
For our 1 to 10 example above, we've used the concatenation 51263478910 with golden sum 1468. But the best reordering of the 1 to 10 blocks is 98471106532 with golden sum 107101 (found by Frank Stevenson).
Here is the beginning of a sequence of such golden sums that might enter the OEIS – all its terms were computed by Frank Stevenson – and I thank him 1000 times!
Best,
É.
___________________________
Frank Stevenson's list for n = 1 to 14:
Available
wooden block(s): 1
Lexicographically
best wooden block(s) arrangement: 1
Best way
to cut in chunk(s) that will minimize the chunks’ sum: 1
Sum of
the chunks: 1
a(1) = 1
S = 1,…
Available
wooden blocks: 1 and 2
Lexicographically
best wooden blocks arrangement: 21
Best way
to cut in chunks that will minimize the chunks’ sum: 21
Sum of
the chunks: 21
a(2) = 21
S = 1,
21,…
Available
wooden blocks: 1, 2 and 3
Lexicographically
best wooden blocks arrangement: 132
Best way
to cut in chunks that will minimize the chunks’ sum: 1+32
Sum of
the chunks: 33
a(3) = 33
S = 1,
21, 33,…
Available
wooden blocks: 1, 2, 3 and 4
Lexicographically
best wooden blocks arrangement: 4321
Best way
to cut in chunks that will minimize the chunks’ sum: 4+321
Sum of
the chunks: 325
a(4) = 325
S = 1,
21, 33, 325,…
Available
wooden blocks: 1, 2, 3, 4 and 5
Lexicographically
best wooden blocks arrangement: 43521
Best way
to cut in chunks that will minimize the chunks’ sum: 43+521
Sum of
the chunks: 564
a(5) = 564
S = 1,
21, 33, 325, 564,…
Available
wooden blocks: 1, 2, 3, 4, 5 and 6
Lexicographically
best wooden blocks arrangement: 154632
Best way
to cut in chunks that will minimize the chunks’ sum: 1+54+632
Sum of
the chunks: 687
a(6) = 687
S = 1,
21, 33, 325, 564, 687,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6 and 7
Lexicographically
best wooden blocks arrangement: 6517432
Best way
to cut in chunks that will minimize the chunks’ sum: 6+51+7432
Sum of
the chunks: 7489
a(7) = 7489
S = 1,
21, 33, 325, 564, 687, 7489,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7 and 8
Lexicographically
best wooden blocks arrangement: 76518432
Best way
to cut in chunks that will minimize the chunks’ sum: 7+651+8432
Sum of
the chunks: 9090
a(8) = 9090
S = 1,
21, 33, 325, 564, 687, 7489, 9090,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8 and 9
Lexicographically
best wooden blocks arrangement: 768519432
Best way
to cut in chunks that will minimize the chunks’ sum: 76+851+9432
Sum of
the chunks: 10359
a(9) = 10359
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10
Lexicographically
best wooden blocks arrangement: 98471106532
Best way
to cut in chunks that will minimize the chunks’ sum: 98+471+106532
Sum of
the chunks: 107101
a(10) = 107101
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359, 107101,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and 11
Lexicographically
best wooden blocks arrangement: 1651142910873
Best way
to cut in chunks that will minimize the chunks’ sum: 1+65+1142+910873
Sum of
the chunks: 912081
a(11) = 912081
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359, 107101, 912081,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12
Lexicographically
best wooden blocks arrangement: 411129101287653
Best way
to cut in chunks that will minimize the chunks’ sum: 41+112+910+1287653
Sum of
the chunks: 1288716
a(12) = 1288716
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359, 107101, 912081, 1288716,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
and 13
Lexicographically
best wooden blocks arrangement: 97864125313121110
Best way
to cut in chunks that will minimize the chunks’ sum: 97+864+1253+13121110
Sum of
the chunks: 13123324
a(13) = 13123324
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359, 107101, 912081, 1288716, 13123324,…
Available
wooden blocks: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
13 and 14
Lexicographically
best wooden blocks arrangement: 4211113109141287653
Best way
to cut in chunks that will minimize the chunks’ sum: 42+111+13109+141287653
Sum of
the chunks: 141300915
a(14) = 141300915
S = 1,
21, 33, 325, 564, 687, 7489, 9090, 10359, 107101, 912081, 1288716, 13123324, 141300915,…
__________________________________
Both lists (sums and arrangements) were submitted a couple of minutes ago to the OEIS by Maximilian Hasler. They are https://oeis.org/A328861 and https://oeis.org/A328862. Many thanks to him too (and to his elegant and short definitions!-)
____________________________________________________________________
Both lists (sums and arrangements) were submitted a couple of minutes ago to the OEIS by Maximilian Hasler. They are https://oeis.org/A328861 and https://oeis.org/A328862. Many thanks to him too (and to his elegant and short definitions!-)
L'idée que développe cette page, m'est venue hier soir alors que je cherchais dans l'OEIS des occurrences du mot "Skolem" (je dois envoyer un petit texte sur le sujet à la revue Tangente). Je suis tombé sur cette suite [https://oeis.org/A143789] qui date de 2008, et j'ai trouvé que sa définition et les premières lignes de la section "Comments" avaient été particulièrement bien écrites (par Dan Hoey). Je me suis demandé ce qu'était devenu Dan, j'ai cliqué sur son nom et lu ceci :
> Dan Hoey made many contributions to the OEIS. It is sad to report that he passed away in 2011. Here is an obituary from the Washington Post.
Cela m'a fait de la peine -- puis je suis tombé sur ceci, par Keith F. Lynch (contributeur lui aussi de l'OEIS)
> Anne Hoey wrote:
I am as you may guess dreadfully sorry to report that Dan Hoey is
dead, and by his own hand. He committed suicide on 31 August.
The police found him in the bath, dead, with blood all over the
bathroom. I have been trying to locate people who knew him. His
two sisters and I are planning a memorial service, also an obituary
in the Washington Post. So much to do, and such a sad business.
We will keep you informed.
Dan was an occasional poster here in the rec.arts.sf.fandom newsgroup
starting in 1992. His last post here was just 26 days ago.
He was a PRSFS member and meeting host, having last hosted the July
meeting. He was the only host to live in DC proper. I learned of his
death when a member received a phone call during last night's meeting
and announced it to the group.
In the '80s and '90s he was a WSFA member. In 1995 he chaired
Disclave, the DC area's premier con from 1950 through 1997.
He was a Wikipedia contributor from 2005 until last month. In his
Wikipedia user page he describes himself:
I'm Dan Hoey, a mathematician, programmer, computer science
researcher, science fiction fan, and wise guy. In 2005-2006, my
Wiki contributions were mostly to Combinatorial game theory, but now
I've decided to be a combinatorial games theorist and so I'll mostly
recuse myself from that fray.
He was a contributor to open source projects.
He had at least one cat in his apartment in DC. I wonder what will
become of it.
I had no idea he was considering suicide.
I will miss him.
--
Keith F. Lynch
____________________
Je dédie donc cette page à Dan, à ses proches et à ses amis.
(Les images de Day-Lewis en boucher ne sont pas très heureuses dans ce contexte, pardon à ceux que cela pourrait choquer).
(Les images de Day-Lewis en boucher ne sont pas très heureuses dans ce contexte, pardon à ceux que cela pourrait choquer).
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